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AIEEA PG and AICE – JRF/SRF (PhD) will be held on June 29 in Computer Based Test (CBT) mode (Representative image/file)
ICAR AIEEA PG Admit Card 2024: Candidates who have registered for the exam can download the hall ticket from the official website exam.nta.ac.in/ICAR/.
The National Testing Agency (NTA) has released the admit cards for All India Entrance Examination (AIEEA PG) and All India Competitive Examination (AICE)-JRF/SRF (PhD) 2024. Candidates who have registered for these exams can download the admit card from the official website exam.nta.ac.in/ICAR/. To download the admit card, candidates have to enter their login details, such as their application number and date of birth. They are further advised to read the instructions given on the hall ticket carefully.
According to the official website, the admit card is issued to the candidates on the condition that they fulfil the eligibility criteria. It will not be sent by post. Candidates are advised not to damage the ICAR AIEEA PG admit card or change any information on it.
ICAR AIEEA PG Admit Card 2024: How to Download
Step 1. Visit the official website of ICAR, which is exam.nta.ac.in/ICAR/.
Step 2. In the Latest News section, you will find the link for AICE JRF/SRF (Ph.D) and AIEEA (PG) Admit Card.
Step 3. A new page will open in which you will be asked to fill in the application number and date of birth.
Step 4. After entering all the details click on “Submit”.
Step 5. Your AIEEA (PG) and AICE JRF/SRF (Ph.D) admit cards will appear on the screen.
Step 6. Download it and take a printout of it for your records.
ICAR AIEEA PG Exam Pattern:
AIEEA PG and AICE – JRF/SRF (Phd) will be conducted on June 29 in Computer Based Test (CBT) mode. AIEEA (PG) is going to be held in the morning, while AICE-JRF/SRF (Ph.D) is scheduled for the afternoon. The duration of the exam will be 2 hours, and there will be a total of 120 questions carrying 480 marks. As per the marking scheme, candidates will get four marks for each correct answer and there will be a penalty of one mark for each wrong answer.
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